(1/6)-(1/2x^2)=(1/3x)

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Solution for (1/6)-(1/2x^2)=(1/3x) equation: 


x in (-oo:+oo)

1/6-((1/2)*x^2) = (1/3)*x // - (1/3)*x

1/6-((1/2)*x^2)-((1/3)*x) = 0

(-1/2)*x^2+(-1/3)*x+1/6 = 0

1/6-1/2*x^2-1/3*x = 0

DELTA = (-1/3)^2-(-1/2*1/6*4)

DELTA = 4/9

DELTA > 0

x = ((4/9)^(1/2)+1/3)/(-1/2*2) or x = (1/3-(4/9)^(1/2))/(-1/2*2)

x = -1 or x = 1/3

x in { -1, 1/3 }

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